(3x+4)(2x^2-13x+21)=0

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Solution for (3x+4)(2x^2-13x+21)=0 equation:


Simplifying
(3x + 4)(2x2 + -13x + 21) = 0

Reorder the terms:
(4 + 3x)(2x2 + -13x + 21) = 0

Reorder the terms:
(4 + 3x)(21 + -13x + 2x2) = 0

Multiply (4 + 3x) * (21 + -13x + 2x2)
(4(21 + -13x + 2x2) + 3x * (21 + -13x + 2x2)) = 0
((21 * 4 + -13x * 4 + 2x2 * 4) + 3x * (21 + -13x + 2x2)) = 0
((84 + -52x + 8x2) + 3x * (21 + -13x + 2x2)) = 0
(84 + -52x + 8x2 + (21 * 3x + -13x * 3x + 2x2 * 3x)) = 0
(84 + -52x + 8x2 + (63x + -39x2 + 6x3)) = 0

Reorder the terms:
(84 + -52x + 63x + 8x2 + -39x2 + 6x3) = 0

Combine like terms: -52x + 63x = 11x
(84 + 11x + 8x2 + -39x2 + 6x3) = 0

Combine like terms: 8x2 + -39x2 = -31x2
(84 + 11x + -31x2 + 6x3) = 0

Solving
84 + 11x + -31x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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